亚马逊笔试题目 - 范文无忧网

[卓越亚马逊集团笔试题]以下是由本站笔试网介绍的笔试题目了 1.为什么希望加入卓越亚马逊? 2.你为什么喜欢软件开发?是什么原因促使你决定选择软件开发作为你的职业? (提示：此题为申请Technical职位...+阅读

笔试题目篇一

1.判断一年是否为闰年的方法

2.非递归实现exists方法

template

class BinaryTree{

protected:

T* _data;

BinaryTree* _left;

BinaryTree* _right;

};

template

class BST:public BinaryTree{

public:

virtual bool exists(const T item const;

};

3.找到下面的bugs

#include

void foo(int a ,char*b)

{

b=(char *)malloc(64);

snprintf(b,you are %d years old!/n,a);

}

int main (void)

{

char *f;

foo(23,f);

printf(%s/n,b);

}

4.Design a subway traffic control system.What objects/classes/modules would you best use for this

purpose?Please draw diagrams and write up class definitions to better illustrate your

design.Write anything additional to clarify your design.

笔试题目篇二

Question:

We he an array representing customers shopping records.

For example, its an array like this:

custA, item1,

custB, item1,

custA, item2,

custB, item3,

custC, item1,

custC, item3,

custD, item2,

This array indicates that customer A bought item 1, customer B bought item 1, customer A bought item 2, customer B bought

item 3, etc..

For a given item X and shopping records array, write code to find out what else (item Y) was bought mostly by the customers

who bought item X.

For example, in above example, if X is item 1 then Y should be item 3.

Rules:

1. One customer can only buy one item once.

2. The mostly brought item should not be item X.

3. If no customer brought item X, then return None

4. If all the customers who brought item X only brought item X, then return None

5. The first line of input is the item X. The second line of input is the shopping record array, this shopping record array is

split by space.

6. If there are many other mostly brought items which he equally brought times, then return any one of those items.

Examples:

Input1:

item1

custA item1 custB item1 custA item2 custB item3 custC item1 custC item3 custD item2

Output1:

item3

Input2:

item2

custA item1 custB item1 custC item1 custA item2 custB item3 custA item3

Output2:

item1

(The output2 can be item3 too)