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基于单片机的数字时钟设计方案

01月17日 编辑 fanwen51.com

[单片机电源电路设计几种方案用7805怎么设计啊]相关资料:7805中文资料 7805稳压电源电路图: 7805管脚图 7805典型应用电路图: 78XX系列集成稳压器的典型应用电路如下图所示,这是一个输出正5V直流电压的稳压电源电路。IC采用集...+阅读

数字钟〔★〕这里用了两种编写方法(即汇编语言与C语言) (1. 开机时,显示12:00:00的时间开始计时;(2. P0.0/AD0控制“秒”的调整,每按一次加1秒; (3. P0.1/AD1控制“分”的调整,每按一次加1分; (4. P0.2/AD2控制“时”的调整,每按一次加1个小时; 2. 电路原理图 3. 系统板上硬件连线 (1. 把“单片机系统”区域中的P1.0-P1.7端口用8芯排线连接到“动态数码显示”区域中的A-H端口上;(2. 把“单片机系统:区域中的P3.0-P3.7端口用8芯排线连接到“动态数码显示”区域中的S1-S8端口上; (3. 把“单片机系统”区域中的P0.0/AD0、P0.1/AD

1、P0.2/AD2端口分别用导线连接到“独立式键盘”区域中的SP

3、SP

2、SP1端口上; 4. 相关基本知识 (1. 动态数码显示的方法 (2. 独立式按键识别过程 (3. “时”,“分”,“秒”数据送出显示处理方法 5. 程序框图 6. 汇编源程序 SECOND EQU 30H MINITE EQU 31H HOUR EQU 32H HOURK BIT P0.0 MINITEK BIT P0.1 SECONDK BIT P0.2 DISPBUF EQU 40H DISPBIT EQU 48H T2SCNTA EQU 49H T2SCNTB EQU 4AH TEMP EQU 4BH ORG 00H LJMP START ORG 0BH LJMP INT_T0 START: MOV SECOND,#00H MOV MINITE,#00H MOV HOUR,#12 MOV DISPBIT,#00H MOV T2SCNTA,#00H MOV T2SCNTB,#00H MOV TEMP,#0FEH LCALL DISP MOV TMOD,#01H MOV TH0,#(65536-2000) / 256 MOV TL0,#(65536-2000) MOD 256 SETB TR0 SETB ET0 SETB EA WT: JB SECONDK,NK1 LCALL DELY10MS JB SECONDK,NK1 INC SECOND MOV A,SECOND CJNE A,#60,NS60 MOV SECOND,#00H NS60: LCALL DISP JNB SECONDK,$ NK1: JB MINITEK,NK2 LCALL DELY10MS JB MINITEK,NK2 INC MINITE MOV A,MINITE CJNE A,#60,NM60 MOV MINITE,#00H NM60: LCALL DISP JNB MINITEK,$ NK2: JB HOURK,NK3 LCALL DELY10MS JB HOURK,NK3 INC HOUR MOV A,HOUR CJNE A,#24,NH24 MOV HOUR,#00H NH24: LCALL DISP JNB HOURK,$ NK3: LJMP WT DELY10MS: MOV R6,#10 D1: MOV R7,#248 DJNZ R7,$ DJNZ R6,D1 RET DISP: MOV A,#DISPBUF ADD A,#8 DEC A MOV R1,A MOV A,HOUR MOV B,#10 DIV AB MOV R1,A DEC R1 MOV A,B MOV R1,A DEC R1 MOV A,#10 MOV R1,A DEC R1 MOV A,MINITE MOV B,#10 DIV AB MOV R1,A DEC R1 MOV A,B MOV R1,A DEC R1 MOV A,#10 MOV R1,A DEC R1 MOV A,SECOND MOV B,#10 DIV AB MOV R1,A DEC R1 MOV A,B MOV R1,A DEC R1 RET INT_T0: MOV TH0,#(65536-2000) / 256 MOV TL0,#(65536-2000) MOD 256 MOV A,#DISPBUF ADD A,DISPBIT MOV R0,A MOV A,R0 MOV DPTR,#TABLE MOVC A,A+DPTR MOV P1,A MOV A,DISPBIT MOV DPTR,#TAB MOVC A,A+DPTR MOV P3,A INC DISPBIT MOV A,DISPBIT CJNE A,#08H,KNA MOV DISPBIT,#00H KNA: INC T2SCNTA MOV A,T2SCNTA CJNE A,#100,DONE MOV T2SCNTA,#00H INC T2SCNTB MOV A,T2SCNTB CJNE A,#05H,DONE MOV T2SCNTB,#00H INC SECOND MOV A,SECOND CJNE A,#60,NEXT MOV SECOND,#00H INC MINITE MOV A,MINITE CJNE A,#60,NEXT MOV MINITE,#00H INC HOUR MOV A,HOUR CJNE A,#24,NEXT MOV HOUR,#00H NEXT: LCALL DISP DONE: RETI TABLE: DB 3FH,06H,5BH,4FH,66H,6DH,7DH,07H,7FH,6FH,40H TAB: DB 0FEH,0FDH,0FBH,0F7H,0EFH,0DFH,0BFH,07FH END 7. C语言源程序 #include unsigned char code dispcode[]={0x3f,0x06,0x5b,0x4f, 0x66,0x6d,0x7d,0x07, 0x7f,0x6f,0x77,0x7c, 0x39,0x5e,0x79,0x71,0x00}; unsigned char dispbitcode[]={0xfe,0xfd,0xfb,0xf7, 0xef,0xdf,0xbf,0x7f}; unsigned char dispbuf[8]={0,0,16,0,0,16,0,0}; unsigned char dispbitcnt; unsigned char second; unsigned char minite; unsigned char hour; unsigned int tcnt; unsigned char mstcnt; unsigned char i,j; void main(void) { TMOD=0x02; TH0=0x06; TL0=0x06; TR0=1; ET0=1; EA=1; while

(1) { if(P0_0==0) { for(i=5;i>0;i--) for(j=248;j>0;j--); if(P0_0==0) { second++; if(second==60) { second=0; } dispbuf[0]=second%10; dispbuf[1]=second/10; while(P0_0==0); } } if(P0_1==0) { for(i=5;i>0;i--) for(j=248;j>0;j--); if(P0_1==0) { minite++; if(minite==60) { minite=0; } dispbuf[3]=minite%10; dispbuf[4]=minite/10; while(P0_1==0); } } if(P0_2==0) { for(i=5;i>0;i--) for(j=248;j>0;j--); if(P0_2==0) { hour++; if(hour==24) { hour=0; } dispbuf[6]=hour%10; dispbuf[7]=hour/10; while(P0_2==0); } } } } void t0(void) interrupt 1 using 0 { mstcnt++; if(mstcnt==8) { mstcnt=0; P1=dispcode[dispbuf[dispbitcnt]]; P3=dispbitcode[dispbitcnt]; dispbitcnt++; if(dispbitcnt==8) { dispbitcnt=0; } } tcnt++; if(tcnt==4000) { tcnt=0; second++; if(second==60) { second=0; minite++; if(...

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