求C语言程序设计实例要100行以上

[c语言程序设计职工工资]你要的是命令行还是图形界面？如果是命令行可以考虑下如果是图形界面的话200分少了点，看看吧.--------------------------------------------既然不是图形界面，代码就简单.不过...+阅读

求C语言程序设计实例要100行以上

Problem Description: The highest building in our city has only one elevator. A request list is made up with N positive numbers. The numbers denote at which floors the elevator will stop, in specified order. It costs 6 seconds to move the elevator up one floor, and 4 seconds to move down one floor. The elevator will stay for 5 seconds at each stop.

For a given request list, you are to compute the total time spent to fulfill the requests on the list. The elevator is on the 0th floor at the beginning and does not have to return to the ground floor when the requests are fulfilled.

Input: There are multiple test cases. Each case contains a positive integer N, followed by N positive numbers. All the numbers in the input are less than 100. A test case with N = 0 denotes the end of input. This test case is not to be processed.

Output Print the total time on a single line for each test case.

Sample Input 1 2 3 2 3 1 0

Sample Output 17 41

Here is my code:

#include int time(int a,int b) { if(a==b)return 0; else if(a

C语言编程100例变形题

#include ＂stdio.h＂#include ＂conio.h＂

main()

{

int i,j,k;

printf(＂\n＂);

for(i=0;i<=8;i++) /*以下为三重循环*/

for(j=0;j<=8;j++)

for (k=0;k<=8;k++)

{

if(i!=1&i!=2&i!=4&i!=5&

j!=6&j!=1&j!=2&j!=4&j!=5&

k!=6&k!=1&k!=2&k!=4&k!=5&k!=6)

{

if (i!=k&i!=j&j!=k)/*确保i、j、k三位互不相同*/

printf(＂%d,%d,%d\n＂,i,j,k);

}

getch();

}

c语言程序设计案例。要100行左右的。

下面是个C++代码。估计你会用上，呵呵。~！~

#include ＂stdio.h＂

#include ＂stdlib.h＂

class Student

{

public:

int id;

int eng;

int math;

int computer;

double avg;

double total;

Student(){id=-1;eng=-1;;math=-1;computer=-1;avg=-1;total=-1;};

double Aveage()

{

return avg=(double)(eng+math+computer)/(double)3;

};

double Sum()

{

return total=(double)(eng+math+computer);

};

void EX(Student*A,Student*B)//排序

{

Student temp;

temp=*A;

*A=*B;

*B=temp;

}

void PX(Student* A,int s)

{

Student* R=new Student[s];

for(int i=0;i

{

for(int j=i+1;j

{

if((A+i)->avg<(A+j)->avg)

EX(A+i,A+j);

}

};

void main()

{

int s=-1;

printf（＂请输入学生个数\n＂）;

scanf(＂%d＂,&s);

Student *all=new Student[s];

printf(＂eng,math,computer\n＂);

for(int i=0;i

{

scanf(＂%d %d %d＂,&(all+i)->eng,&(all+i)->math,&(all+i)->computer）；//输入以空格为间隔以回车为确定

(all+i)->Aveage();(all+i)->Sum();(all+i)->id=i+1;

}

PX(all,s);

printf(＂ID,eng,math,computer,avg,total\n＂);

for(int j=0;j

{

printf(＂%d,%d,%d,%d,%2.2f,%d\n＂,(all+j)->id,(all+j)->eng,(all+j)->math,(all+j)->computer,(all+j)->avg,(all+j)->total);

}

c语言程序经典实例

#include

void printk(void)

{

printf(＂＂);

}

void printx(void)

{

printf(＂*＂);

}

void main()

{

int n,i,j;

printf(＂Please input n:＂);

scanf(＂%d＂,&n);

for (i = 0;i <= 2*n;i++)

{

if (i <= n)

{

for (j = 0;j < n-i;j++)

{

printk();

}

for(j = 0;j < 2*i+1;j++)

{

printx();

}

printf(＂\n＂);

}

if (i > n)

{

for (j = 0;j <= i-n-1;j++)

{

printk();

}

for (j = 0;j < 2*(2*n-i)+1;j++)

{

printx();

}

printf(＂\n＂);

}